The GRE maths select one or more answers question given below is from the topic number properties. It tests the concept of finding the Common Factors of a set of numbers by finding out the factors of the HCF of those numbers.

Question 3: Which of the following numbers are factors common to 108, 288, and 396?

Indicate __all__ such numbers

- 72
- 24
- 36
- 8
- 12
- 9

From INR 2999

**Prime factorize 108, 288, and 396**

108 = 2^{2} × 3^{3}

288 = 2^{5} × 3^{2}

396 = 2^{2} × 3^{2} × 11

**HCF is the product of the lowest power of common prime factors of the numbers.**

HCF(108, 288, 396) = 2^{2} × 3^{2} = 36

HCF(108, 288, 396) = 36

The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36

From the given options, 9, 12, and 36 are factors common to all the three numbers.

**Choices C, E, and F are the factors common to all the three numbers.**

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