# GMAT Questionbank | GMAT Inequalities Q3

#### Inequalities in Quadratic Expressions | GMAT Sample Questions

This GMAT quant practice question is a problem solving question from Inequalities. Concept: Inequality of algebraic expressions. A GMAT 650 quantitative reasoning sample question.

Question 3: What is the smallest integer that satisfies the inequality $$frac{x - 3}{x^2 - 8x - 20}$ > 0? 1. -2 2. 10 3. 3 4. -1 5. 0 ## Get to 705+ in the GMAT #### Online GMAT Course @ INR 6000 ### Video Explanation ## GMAT Live Online Classes #### Starts Sun, Mar 3, 2024 ### Explanatory Answer | GMAT Inequalities of Quadratic Expression Let us factorize the denominator and rewrite the expression as $\frac{x - 3}{$x - 10$(x + 2)}) > 0
Approach: Equate each of the terms of the expression to zero to identify the values of x in which the inequality holds good.
The values that are relevant to us are x = 3, x = 10 and x = -2.

Let us arrange these values in ascending order: -2, 3 and 10.
The quickest way to solve inequalities questions after arriving at these values is verifying whether the inequality holds good at the following intervals.

Interval 1: x < -2.
Pick a value in that range and check whether the inequality holds good.
Let us take x = -10. When x = -10, the value of $$frac{x - 3}{$x - 10$(x + 2)}) is $$frac{-10 - 3}{$-10 - 10$(-10 + 2)}).
The value of the expression in this interval is negative; the inequality DOES NOT hold good in this interval.

Interval 2: -2 < x < 3.
Let us take x = 0. When x = 0, $$frac{x - 3}{$x - 10$(x + 2)}) = $$frac{0 - 3}{$0 - 10$(0 + 2)}) > 0; the inequality holds good in this interval.
We found that the inequality holds good in the interval -2 < x < 3
The least integer value that x can take in the interval -2 < x < 3 is x = -1.

So, the correct answer is -1.

Remember: We have to find out the least integer value. And we have arrived at -1.
Do not waste time computing the entire range of values of x that satisfy the inequality.

Note: In any inequality question, when the question asks us to determine the intervals in which the inequality holds good, we have to eliminate values of x that will result in the denominator becoming zero.

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