This GMAT quant practice question is a problem solving question in Geometry. Concept: Property pertaining to the sides of an acute triangle.

#### Question: If 10, 12 and 'x' are sides of an acute angled triangle, how many integer values of 'x' are possible?

- 7
- 12
- 9
- 13
- 11

#### Explanatory Answer

Video explanation will be added soon#### Key property about sides of an acute triangle

Finding the answer to this question requires that you know this key property about sides of an acute triangle.

For an acute angled triangle, the square of the LONGEST side MUST BE LESS than the sum of squares of the other two sides.

If 'a', 'b', and 'l' are the 3 sides of an acute triangle where 'l' is the longest side then l^{2} < a^{2} + b^{2}

The sides are 10, 12, and 'x'.

**Scenario 1:** Among the 3 sides 10, 12, and x, for values of x ≤ 12, 12 is the longest side.

**Scenario 2:** For values of x > 12, x is the longest side

##### Possibilities in scenario 1:

When x ≤ 12, let us find the number of values for x that will satisfy the inequality 12^{2} < 10^{2} + x^{2}

i.e., 144 < 100 + x^{2}

The least integer value of x that satisfies this inequality is 7.

The inequality will hold true for x = 7, 8, 9, 10, 11, and 12. i.e., 6 values.

##### Possibilities in scenario 2:

When x > 12, x is the longest side.

Let us count the number of values of x that will satisfy the inequality x^{2} < 10^{2} + 12^{2}

i.e., x^{2} < 244

x = 13, 14, and 15 satisfy the inequality. That is 3 more values.

Hence, the values of x for which 10, 12, and x will form sides of an acute triangle are x = 7, 8, 9, 10, 11, 12, 13, 14, 15. A total of 9 values.

Choice C is the correct answer.

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