GMAT Math Questions | Coordinate Geometry Q1

Equation of Circle | GMAT Sample Questions

The question given below is a GMAT Math problem solving question in Coordinate Geometry. The radius of the circle and the coordinates of the center of the circle are provided. The task is to find the equation of the circle. This GMAT sample question is an easy question - a GMAT sub 600 level question.

Question 1: What is the equation of a circle whose radius is 6 units and is centered at (3, 2)?

  1. x2 + y2 + 6x - 4y = 23
  2. x2 + y2 - 6x + 4y = 23
  3. x2 + y2 + 6x + 4y = 23
  4. x2 + y2 - 6x - 4y = -23
  5. x2 + y2 - 6x - 4y = 23

Get to 705+ in the GMAT


Online GMAT Course
@ INR 6000


Video Explanation


GMAT Live Online Classes


Starts Sun, Mar 3, 2024


Explanatory Answer | GMAT Equation of Circle

Generalized form of equation of a circle

Equation of a circle with center (a, b) and radius 'r' units is (x - a)2 + (y - b)2 = r2
Therefore, the equation of this circle = (x - 3)2 + (y - 2)2 = 62
i.e., x2 - 6x + 9 + y2 - 4y + 4 = 36
or x2 + y2 - 6x - 4y = 23

Choice E is the correct answer.



GMAT Online Course
Try it free!

Register in 2 easy steps and
Start learning in 5 minutes!

★ Sign up

Already have an Account?

★ Login

GMAT Live Online Classes

Next Batch Mar 3, 2024

★ GMAT Live Info

GMAT Coordinate Geometry Videos On YouTube


GMAT Sample Questions | Topicwise GMAT Questions


Work @ Wizako

How to reach Wizako?

Mobile: (91) 95000 48484
WhatsApp: WhatsApp Now
Email: learn@wizako.com
Leave A Message