GMAT Math Questions | Coordinate Geometry Q1

Equation of Circle | GMAT Sample Questions

The question given below is a GMAT Math problem solving question in Coordinate Geometry. The radius of the circle and the coordinates of the center of the circle are provided. The task is to find the equation of the circle. This GMAT sample question is an easy question - a GMAT sub 600 level question.

Question 1: What is the equation of a circle whose radius is 6 units and is centered at (3, 2)?

  1. x2 + y2 + 6x - 4y = 23
  2. x2 + y2 - 6x + 4y = 23
  3. x2 + y2 + 6x + 4y = 23
  4. x2 + y2 - 6x - 4y = -23
  5. x2 + y2 - 6x - 4y = 23

Get to Q51 in GMAT Quant


Online GMAT Course
@ INR 3500


Video Explanation


GMAT Live Online Classes


Starts Tue, Oct 12, 2021


Explanatory Answer | GMAT Equation of Circle

Generalized form of equation of a circle

Equation of a circle with center (a, b) and radius 'r' units is (x - a)2 + (y - b)2 = r2
Therefore, the equation of this circle = (x - 3)2 + (y - 2)2 = 62
i.e., x2 - 6x + 9 + y2 - 4y + 4 = 36
or x2 + y2 - 6x - 4y = 23

Choice E is the correct answer.



GMAT Online Course
Try it free!

Register in 2 easy steps and
Start learning in 5 minutes!

★ Sign up

Already have an Account?

★ Login

GMAT Live Online Classes

Next Batch Oct 12, 2021

★ GMAT Live Info

GMAT Coaching in Chennai

Next Batch
after Lockdown

★ GMAT Class Info

GMAT Coaching in Chennai

Sign up for a Free Demo of our GMAT Classes in Chennai

★ Schedule Demo

GMAT Coordinate Geometry Videos On YouTube


GMAT Sample Questions | Topicwise GMAT Questions


Where is Wizako located?

Wizako - GMAT, GRE, SAT Prep
An Ascent Education Initiative
14B/1 Dr Thirumurthy Nagar 1st Street
Nungambakkam
Chennai 600 034. India

How to reach Wizako?

Phone: (91) 44 4500 8484
Mobile: (91) 95000 48484
WhatsApp: WhatsApp Now
Email: learn@wizako.com
Leave A Message