The question given below is a GMAT Math problem solving qusetion in Coordinate Geometry. The radius of the circle and the coordinates of the center of the circle are provided. The task is to find the equation of the circle.
- x2 + y2 + 6x - 4y = 23
- x2 + y2 - 6x + 4y = 23
- x2 + y2 + 6x + 4y = 23
- x2 + y2 - 6x - 4y = -23
- x2 + y2 - 6x - 4y = 23
Explanatory AnswerVideo explanation will be added soon
Generalized form of equation of a circle
Equation of a circle with center (a, b) and radius 'r' units is (x - a)2 + (y - b)2 = r2
Therefore, the equation of this circle = (x - 3)2 + (y - 2)2 = 62
i.e., x2 - 6x + 9 + y2 - 4y + 4 = 36
or x2 + y2 - 6x - 4y = 23
Choice E is the correct answer.