This GMAT sample question is a quant problem solving question in Linear Equations. Concept tested: Finding the number of solutions for linear equations where one of the unknowns is the absolute value (modulus) of a variable. A medium difficulty, 650 to 700 level GMAT practice question in algebra.

Question 12 : If x > 0, how many integer values of (x, y) will satisfy the equation 5x + 4|y| = 55?

- 3
- 6
- 5
- 4
- Infinitely many

@ INR

5x + 4|y| = 55

The equation can be rewritten as 4|y| = 55 - 5x.

**Inference 1**: Because |y| is non-negative, 4|y| will be non-negative.

Therefore, (55 - 5x) cannot take negative values.

**Inference 2**: Because x and y are integers, 4|y| will be a multiple of 4.

Therefore, (55 - 5x) will also be a multiple of 4.

**Inference 3**: 55 is a multiple of 5. 5x is a multiple of 5 for integer x.

So, 55 - 5x will always be a multiple of 5 for any integer value of x.

**Combining Inference 2 and Inference 3**: 55 - 5x will be a multiple of 4 and 5.

i.e., 55 - 5x will be a multiple of 20.

1. x = 3, 55 - 5x = 55 - 15 = 40.

2. x = 7, 55 - 5x = 55 - 35 = 20

3. x = 11, 55 - 5x = 55 - 55 = 0.

When x = 15, (55 - 5x) = (55 - 75) = -20.

Because (55 - 5x) has to non-negative, x = 15 or values greater than 15 are not possible.

So, x can take only 3 values viz., 3, 7, and 11.

We have 3 possible values for 55 - 5x. So, we will have these 3 values possible for 4|y|.

**Possibility 1**: 4|y| = 40 or |y| = 10. So, y = 10 or -10.

**Possibility 2**: 4|y| = 20 or |y| = 5. So, y = 5 or -5.

**Possibility 3**: 4|y| = 0 or |y| = 0. So, y = 0.

Number of values possible for y = 5.

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